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(FRTC, 11-cos30°1 + cos30°ho = sec60° + tan60° |
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Answer» LHS : sqrt[(1 + cos30)/ (1 - cos 30)] = sqrt[(1 + cos30)^2/ (1 - cos^2 30)] = sqrt[(1 + cos30)^2/ (sin^2 30)] = (1 + cos30)/ sin 30) = cosec 30 + cot 30 = sec(90-30) + tan(90-30) = sec 60 + tan 60 = RHS Hence proved |
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