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From what value of k , -4 is Zeroes of the polynomial x²-x-(2k+2) |
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Answer» Answer: K = 9 Step-by-step explanation: f(x) = x² - x - (2k +2) f(-4) = (-4)² -(-4) - (2k + 2) 0 = 16 + 4 - 2k - 2 0 = 18 - 2k 2k = 18 k = 18 ÷ 2 ∴ k = 9 |
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