Saved Bookmarks
| 1. |
From the two e.m.f. Equation `e_(1)=E_(0) sin (100 pi t)` and `e_(2)=E_(0)sin (100 pi t+(pi)/3)`, we find thatA. `e_(1) "leads" e_(2) "by" 60^(@)`B. `e_(2) "lags behind" e_(1) "by" 60^(@)`C. `e_(2)` achieves its maximum value `1/300` second before `e_(1)`D. `e_(1)` achieves its maximum value `1/300` second before `e_(2)` |
|
Answer» Correct Answer - C For both, `omega t = 2 pi f t = 100 pi t` `:. F = 50 Hz :. T = 1/50 s` For a phase diff. = `2 pi`, time required = `T = 1/50 s` `:.` For a phase diff. of `(pi)/3`, time = `(pi)/3 xx 1/50 xx 1/(2 pi) = 1/300 s`. |
|