From the top of a hill 200 m high, the angles of depression of the top

1.	From the top of a hill 200 m high, the angles of depression of the top and the bot tomof a pillar are 30° and 60° respectively. Find the height of the pillar and its distancefrom the hill. (Take V3 = 1.732]
Answer» Step-by-step explanation: Let CE is a pole of height H meter. AD is a hill of height 200 m. Let distance between bottom of hill to pole = x m. According to question ∠XAC= 30° = ∠ACB and ∠XAE = 60° = ∠AED From right angled ∆ADE TAN 60° = AD/DE ⇒ √81 = 200/x ⇒ x = 200/√3 m From right angled ∆ABC, HENCE, height of pole = 133.33 m.

From the top of a hill 200 m high, the angles of depression of the top and the bot tomof a pillar are 30° and 60° respectively. Find the height of the pillar and its distancefrom the hill. (Take V3 = 1.732]

Answer»

Step-by-step explanation:

Let CE is a pole of height H meter. AD is a hill of height 200 m.

Let distance between bottom of hill to pole = x m.

According to question

∠XAC= 30° = ∠ACB and ∠XAE = 60° = ∠AED

From right angled ∆ADE

TAN 60° = AD/DE

⇒ √81 = 200/x

⇒ x = 200/√3 m

From right angled ∆ABC,

HENCE, height of pole = 133.33 m.

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From the top of a hill 200 m high, the angles of depression of the top and the bot tomof a pillar are 30° and 60° respectively. Find the height of the pillar and its distancefrom the hill. (Take V3 = 1.732]​

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From the top of a hill 200 m high, the angles of depression of the top and the bot tomof a pillar are 30° and 60° respectively. Find the height of the pillar and its distancefrom the hill. (Take V3 = 1.732]