From the sum of 11a³-8b² and 4a³+6b²subtract the sum of 9a³+b²an

1.	From the sum of 11a³-8b² and 4a³+6b²subtract the sum of 9a³+b²and 3a³-4b²
Answer» QUESTION: $= > ((11 {a}^{3} - 8 {b}^{2} ) + (4 {a}^{3} + 6 {b}^{2} )) - ((9 {a}^{3} + {b}^{2} ) + (3 {a}^{3} - 4 {b}^{2} ))$ ANSWER: $= > ((11 {a}^{3} - 8 {b}^{2} ) + (4 {a}^{3} + 6 {b}^{2} )) - ((9 {a}^{3} + {b}^{2} ) + (3 {a}^{3} - 4 {b}^{2} ))$ $= > ((15 {a}^{3} - 2 {b}^{2} ) - (12 {a}^{ 3} - 3 {b}^{2} ))$ $= > 3 {a}^{3} + {b}^{2}$ HOPE this answer HELPS you ^_^ !