Saved Bookmarks
| 1. |
From the choices given below, choose the equation whose graph is given fig:(i) y = x + 2 (ii) y = x – 2 (iii)y = – x + 2 (iv) x + 2y = 6 |
|
Answer» Given: (-1, 3) and (2, 0) are the solution of one of the following given equations. Check which equation satisfy both the points. (i) y = x + 2 Putting, x = -1 and y = 3 3 ≠ – 1 + 2 L.H.S ≠ R.H.S Putting, x = 2 and y = 0 0 ≠ 4 L.H.S ≠ R.H.S Thus, this solution does not satisfy the given equation. (ii) y = x – 2 Putting, x = -1 and y = 3 3 ≠ – 1 – 2 L.H.S ≠ R.H.S Putting, x = 2 and y = 0 0 = 0 L.H.S = R.H.S Thus, the given solutions does not satisfy this equation completely. (iii) y = – x + 2 Putting, x = – 1 and y = 3 3 = – ( – 1 ) + 2 L.H.S = R.H.S Putting x = 2 and y = 0 0 = -2 + 2 0 = 0 L.H.S = R.H.S Therefore, (0, 2) and (-1,3) satisfy this equation. Hence, this is the graph for equation y = -x + 2. |
|