From P(–4, 0), tangents PA and PA′ are drawn to a circle, x2+y2=4.

1.	From P(–4, 0), tangents PA and PA′ are drawn to a circle, x2+y2=4. Where A and A′ is point of contact and A lies above x-axis. Rhombus PAP′A′ is completed. Column-IColumn-IIColumn-III(I)A≡(−1,√3)(i)PA=2√3(P)P′ lies on the circle, x2+y2=4(II)A′≡(−1,−√3)(ii)Area of ΔPAA′=3√3 sq.units(Q)ΔPAA′ is equilateral(III)P′=(4,0)(iii)PP′=6(R)P′ lies outside the circle , x2+y2=4(IV)P′=(2,0)(iv)Area of ΔPAA′=4√3 sq.units(S)P′ lies inside circle , x2+y2=4 Which one of the following is correct?
Answer» From $P (- 4, 0)$ , tangents $P A$ and $P A^{'}$ are drawn to a circle, $x^{2} + y^{2} = 4$ . Where $A$ and $A^{'}$ is point of contact and $A$ lies above x-axis. Rhombus $P A P^{'} A^{'}$ is completed. $\begin{matrix} Column-I & Column-II & Column-III (I) & A \equiv (- 1, \sqrt{3}) & (i) & P A = 2 \sqrt{3} & (P) & P^{'} lies on the circle, x^{2} + y^{2} = 4 (I I) & A^{'} \equiv (- 1, - \sqrt{3}) & (i i) & Area of Δ P A A^{'} = 3 \sqrt{3} sq.units & (Q) & Δ P A A^{'} is equilateral (I I I) & P^{'} = (4, 0) & (i i i) & P P^{'} = 6 & (R) & P^{'} lies outside the circle, x^{2} + y^{2} = 4 (I V) & P^{'} = (2, 0) & (i v) & Area of Δ P A A^{'} = 4 \sqrt{3} sq.units & (S) & P^{'} lies inside circle, x^{2} + y^{2} = 4 \end{matrix}$ Which one of the following is correct?

From P(–4, 0), tangents PA and PA′ are drawn to a circle, x2+y2=4. Where A and A′ is point of contact and A lies above x-axis. Rhombus PAP′A′ is completed. Column-IColumn-IIColumn-III(I)A≡(−1,√3)(i)PA=2√3(P)P′ lies on the circle, x2+y2=4(II)A′≡(−1,−√3)(ii)Area of ΔPAA′=3√3 sq.units(Q)ΔPAA′ is equilateral(III)P′=(4,0)(iii)PP′=6(R)P′ lies outside the circle , x2+y2=4(IV)P′=(2,0)(iv)Area of ΔPAA′=4√3 sq.units(S)P′ lies inside circle , x2+y2=4 Which one of the following is correct?

Answer»

From $P (- 4, 0)$ , tangents $P A$ and $P A^{'}$ are drawn to a circle, $x^{2} + y^{2} = 4$ . Where $A$ and $A^{'}$ is point of contact and $A$ lies above x-axis. Rhombus $P A P^{'} A^{'}$ is completed.

$\begin{matrix} Column-I & Column-II & Column-III (I) & A \equiv (- 1, \sqrt{3}) & (i) & P A = 2 \sqrt{3} & (P) & P^{'} lies on the circle, x^{2} + y^{2} = 4 (I I) & A^{'} \equiv (- 1, - \sqrt{3}) & (i i) & Area of Δ P A A^{'} = 3 \sqrt{3} sq.units & (Q) & Δ P A A^{'} is equilateral (I I I) & P^{'} = (4, 0) & (i i i) & P P^{'} = 6 & (R) & P^{'} lies outside the circle, x^{2} + y^{2} = 4 (I V) & P^{'} = (2, 0) & (i v) & Area of Δ P A A^{'} = 4 \sqrt{3} sq.units & (S) & P^{'} lies inside circle, x^{2} + y^{2} = 4 \end{matrix}$

Which one of the following is correct?

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