1.

From ideal instruments, current measured is `I = 10.0` amp, potential difference measured is `V = 100.0` volt, length of wire is `31.4 cm`, and diameter of wire is `2.00 mm`, the resistivity of wire will be (in correct significant figure) `(pi = 3.14)`A. `1.00 xx 10^(-4) Omega - m`B. `1.0 xx 10^(-4) Omega - m`C. `1 xx 10^(-4) Omega - m`D. `1.000 xx 10^(-4) Omega - m`

Answer» Correct Answer - C
`rho = (pi D^(2))/(4L) (v)/(i) = ((3.14)(2.00 xx 10^(-3))^(-2))/(4(0.314)) ((100.0)/(10.0))`
`rho = 1.00 xx 10^(-4) Omega - m`


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