1.

From a top of the tower 40 m high, a body is thrown vertically upwards with a velocity of 10 m per second. How much time does the body takes to reach the ground. What is its velocity just before it hits the ground. (g=10 m per second) ​

Answer» HAY MATE UR ANSWER IS HERE HEIGHT OR DISTANCE =40M OR S=40MU=10V=0 V IS 0 BECOZ AFTER GOING UPWARDS THE BODY COMES DOWN AT REST NOW FIND THE ACCELERATION THE FORMULA IS V*2-U*2=2AS0-100=2×A×40-100= 80A -100/80=AA=-5/4NOW FIND TIME BY USING FORMULA A=V-U/T-5/4=0-10/T-5/4T=-10T= 8M^S*-PLZ FOLLOW ME PLZ MARK ME AS THE BRAINIEST


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