From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm,

1.	From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)
Answer» ONG>ANSWER: In right △AED, using Pythagoras THEOREM, AD2=AE2+DE2=92+122=81+144=225cm ⇒AD=225=15cm=diameter Required area = ar. ABCD + ar. semi-circle - ar △AED=(20×15)+21×722×(215)2−21×9×12 =300+88.3928−54=334.3928cm²

From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)

Answer» ONG>ANSWER:

In right △AED, using Pythagoras THEOREM,

AD2=AE2+DE2=92+122=81+144=225cm

⇒AD=225=15cm=diameter

Required area = ar. ABCD + ar. semi-circle - ar △AED=(20×15)+21×722×(215)2−21×9×12

=300+88.3928−54=334.3928cm²

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From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)​

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From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)