From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut

1.	From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut off. What is thelength of the remaining log?(with calculation )
Answer» Answer: 3.1 m Step-by-step EXPLANATION: TOTAL LENGTH = 11 m Length of the FIRST piece = 23/5 m = 4.6 m Length of the SECOND piece = 33/10 m = 3.3 m Therefore, Remaining length = (11 - 4.6 - 3.3) m = 3.1 m

From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut off. What is thelength of the remaining log?(with calculation )

Answer»

Answer:

3.1 m

Step-by-step EXPLANATION:

TOTAL LENGTH = 11 m

Length of the FIRST piece = 23/5 m = 4.6 m

Length of the SECOND piece = 33/10 m = 3.3 m

Therefore,

Remaining length = (11 - 4.6 - 3.3) m

= 3.1 m

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From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut off. What is thelength of the remaining log?(with calculation )

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