Saved Bookmarks
| 1. |
From a horizontal tube with area of cross-section `A_(1)` and `A_(2)` as shosn in fiugre liquid is flowing in the level of the liauid in the two veritcal tunes is h. A. The volume of the liquid flowing through the tube in time is `A_(1)v_(1)`B. `v_(2)-v_(1)=sqrt(2gh)`C. `v_(2)^(2)-v_(1)^(1)=2gh`D. The energy per unit mass of the liquid is the same in both sections of the tube |
|
Answer» (c) `(p_(1))/(rho)+(v_(1)^(2))/(2)=(p_(2))/(rho)+(v_(2)^(2))/(2)` or` " " p_(1)-p_(2)=(rho)/(2)(v_(2)^(2)-v_(1)^(2))` But `" " p_(1)-p_(2)=rhogh=(rho)/(2)(v_(2)^(2)-v_(1)^(2))` or `" " v_(2)^(2)-v_(1)^(2)=2gh` |
|