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From a disc of mass 'm' and radius 'r'. A circular portion of radius (r )/(3) is removed from the edges. Find the M.I of the remaining system about a normal through centre of original disc |
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Answer» Solution :Let `I_(2)` be the M.I of REMAINING poriton. M.I. of the removed PARITON about a normal axis through center of the ORIGINAL disc is `I_(1)=((m)/(9)((R)/(3))^(2))/(2)+(m)/(9)((2r)/(3))^(2)` or `I_(1)=(mr^(2))/(18)` Hence , M.I. of the remaining portion is `I_(2)=I-I_(1)=(mr^(2))/(2)-(mr^(2))/(18)` or `I_(2)=(4mr^(2))/(9)` |
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