1.

from a cord of 16 m length two pieces of lengths 3 1/3m and 2 2/5m are cut off find the length of the remaining cord ​

Answer»

TOTAL length of the cord = 16 m

length of first piece CUT down = 31/3m

length of SECOND piece cut down = 22/5m

total length cut down from the cord = length of first piece + second

= (31/3)+(22/5)m

= (155 + 66)/15

= 221/15

remaining length of cord =

total length of cord - cut off length

= 16 or (16/1) - (221/15)m

= (240 - 221)/15 m

= 19/15 m

or,

1.26667 m


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