Friction between any two surfacesin contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them F prop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta A horizontal force of 1.2kg is applied on a 1.5kg block which rests on a horizontal surface If the coefficient of friction is 0.3 force of friction is .

Friction between any two surfacesin contact is the force that opposes

1.	Friction between any two surfacesin contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them F prop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta A horizontal force of 1.2kg is applied on a 1.5kg block which rests on a horizontal surface If the coefficient of friction is 0.3 force of friction is .
Answer» `0.45kgf` `1.2kgf` `1.5kgf` `0.3kgf` SOLUTION :`F = MUR = MU (mg) = 0.3 XX 1.5kg = 0.45kg f` .