Friction between any two surfacesin contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them Fprop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta The acceleration produce in the block in the above question is .

Friction between any two surfacesin contact is the force that opposes

1.	Friction between any two surfacesin contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them Fprop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta The acceleration produce in the block in the above question is .
Answer» `9.8ms^(-2)` `0.3ms^(-2)` `1.5ms^(-2)` `4.9ms^(-2)` Solution :FORCE producing ACCELERATION `f=` APPLIED force - force of friction `=1.2 -0.45 = 0.75 kg f = 0.75 XX 9.8 N` `a = (f)/(m) = (0.75 xx 9.8)/(1.5) = 4.9ms^(-2)` .