Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Find the maximum speed of the particle: (g=10m//s^(2))

Frequency of a particle executing SHM is 10 Hz. The particle is suspen

1.	Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Find the maximum speed of the particle: (g=10m//s^(2))
Answer» Solution :Mean POSITION of the PARTICLE is `(mg)/k` distance below unstretched position of spring. Therefore, AMPLITUDE of oscillation is `A=(mg)/k""omega=sqrt(k/m)=2pif=20pi` `:.m/k=1/(400pi^(2))` Therefore the maximum SPEED of particle will be `v_("MAX")=A omega=(g/(400pi^(2)))(20pi)=1/(2pi)m//s`