Saved Bookmarks
| 1. |
Freqency of dominant allele is 0.6 find heterozygous frequency |
|
Answer» 0.48Explanation:here p = 0.6then p2 = 0.36 q = 0.4then Q2 = 0.16 Now ACCORDING to herdy Weinberg EQUATION we KNOW : p2+2pq+q2 = 1then , here 2pq = 1-(0.36+0.16 ) = 0.48 |
|