\frac{x+3}{x-3}+6\left(\frac{x-3}{x+3}\right)=5, x \neq 3 – InterviewSolution

1.	\frac{x+3}{x-3}+6\left(\frac{x-3}{x+3}\right)=5, x \neq 3
Answer» (nn+6n+9)+6(nn-6n+9)=5(nn-9)7nn-30n+63=5nn-452nn-30n+108=0n*n-15n+54=0(n-6)(n-9)=0so n=6 or 9

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