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\frac{x+3}{x-3}+6\left(\frac{x-3}{x+3}\right)=5, x \neq 3,-3 |
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Answer» (x*x+6x+9)+6(x*x-6x+9)=5(x*x-9)7x*x-30x+63=5x*x-452x*x-30x+108=0x*x-15x+54=0(x-9)(x-6)=0x=6 or 9 |
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