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\frac{\tan \left(\frac{\pi}{4}+\theta\right)+\tan \left(\frac{\pi}{4}-\theta\right)}{\tan \left(\frac{\pi}{4}+\theta\right)-\tan \left(\frac{\pi}{4}-\theta\right)}=\csc 2 \theta\frac{\sin (A+B)}{\sin (A-B)}=\frac{\alpha+\beta}{\alpha-\beta}, \text { show that } \frac{\tan A}{\tan B}=\frac{\alpha}{\beta} |
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Answer» i)use formula tan ((pi)/4 +x)=(1+tan x)/(1-tan x)and tan ((pi)/4-x)=(1-tan x)/(1+tan x) |
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