\frac { \tan ^ { 3 } \alpha } { 1 + \tan ^ { 2 } \alpha } + \frac { \c – InterviewSolution

1.	\frac { \tan ^ { 3 } \alpha } { 1 + \tan ^ { 2 } \alpha } + \frac { \cot ^ { 3 } \alpha } { 1 + \cot ^ { 2 } \alpha } = \sec \alpha \csc ( \alpha - 2 \sin \alpha \cos a
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