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\frac { \operatorname { cot } A + \operatorname { tan } B } { \operatorname { cot } B + \operatorname { tan } A } = \operatorname { cot } A \operatorname { tan } B |
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Answer» cotA=1/tanAcotB=1/tanBputting in the eq.=(1/tanA +tanB)/(1/tanB +tanA)=((1+tanAtanB)/tanA)/((1+tanAtanB)/tanB)=tanB/tanA=cotA tanB |
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