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\frac{\cot \theta+\cosec \theta-1}{\cot \theta-\cosec \theta+1}=\frac{1+\cos \theta}{\sin \theta} |
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Answer» Cosec A + cot A - 1 / cot A - cosec A + 1we know that,cosec ² A - cot ² A = 1substituting this in the numeratorcosec A + cot A -(cosec ² A - cot ² A) / (cot A - cosec A + 1)x²-y²= (x+y)(x-y)cosec A + cot A - (cosec A + cot A) (cosec A - cot A) / (cot A - cosec A + 1)taking common(cosec A + cot A)(1-cosec A + cot A) / (cot A - cosec A + 1)cancelling like terms in numerator and denominatorwe are left with cosec A + cot A= 1/sin A + cos A/sin A= (1+cos A) / sin A not understood plzz explain it clearly thanku sister.... |
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