\frac{9^{n} \times 3^{2} \times 3^{n}-(27)^{n}}{3^{3 m} \times 2^{3}}= – InterviewSolution

1.	\frac{9^{n} \times 3^{2} \times 3^{n}-(27)^{n}}{3^{3 m} \times 2^{3}}=3^{-3}, \text { prove that }(m-n)=1
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