1.

\frac { 5 ^ { 2 ( n + 6 ) } \times ( 25 ) ^ { 2 n - 7 } } { ( 125 ) ^ { 2 n } }

Answer»

= 5^2(n+6) * (5^2)^2n-7/ (5^3)^2n

= 5^ 2n+12+4n-14 / 5^6nAs bases are same, powers can be equated

= 6 n - 2 - 6 n = -2.



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