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\frac{4}{x-3}-\frac{3}{x-1}=\frac{5}{x-1}-\frac{4}{x-2} |
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Answer» (4x-4-3x+9)/((x-3)(x-1))=(5x-10-4x+4)/((x-1)(x-2))(x+5)/(x-3)=(x-6)/(x-2)x*x+3x-10=x*x-9x+1812x=28x=28/12=(7×4)/(3×4)=7/3 |
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