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\frac{2 \sin 68^{\circ}}{\cos 22}-\frac{2 \cot 15}{5 \tan 75}-\frac{3 \tan 45 \tan 20^{\circ} \tan 40^{\circ} \tan 50^{\circ} \tan 70^{\circ}}{5}=1 |
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Answer» sin68= cos72tan15 = cot75tan50 = cot40tan20= cot70as these all follow compliment ruleso after putting the value2-2/5-3/52-1= 1 |
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