\frac{(1+\sin \theta)^{2}+(1-\sin \theta)^{2}}{2 \cos ^{2} 0}=\frac{1+ – InterviewSolution

1.	\frac{(1+\sin \theta)^{2}+(1-\sin \theta)^{2}}{2 \cos ^{2} 0}=\frac{1+\sin ^{2} \theta}{1-\sin ^{2} 0}
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