\frac { 1 + \operatorname { sec } 2 \theta } { \operatorname { lan } 2 – InterviewSolution

1.

\frac { 1 + \operatorname { sec } 2 \theta } { \operatorname { lan } 20 } = \operatorname { cot } \theta

Answer»

L.H.S.=(1+1/cos2x)/(sin2x/cos2x) =(1+cos2x)(sin2x) =2cos^2x/2sinxcosx =cosx/sinx =cotx =R.H.S.Hence Proved

please explain the third step, Kadambari

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