\frac{1}{2} \tan ^{-1} x=\cos ^{-1}\left[\frac{1+\sqrt{1+x^{2}}}{2 \sq – InterviewSolution

1.	\frac{1}{2} \tan ^{-1} x=\cos ^{-1}\left[\frac{1+\sqrt{1+x^{2}}}{2 \sqrt{1+x^{2}}}\right]^{2}
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