\frac 1 2 [ 2 ( k %2B 3 ) %2B 4 ( - 3 - 3 ) %2B 6 ( 3 - k ) ] – InterviewSolution

1.	\frac 1 2 [ 2 ( k %2B 3 ) %2B 4 ( - 3 - 3 ) %2B 6 ( 3 - k ) ] = 0
Answer» 1/2[2(k + 3)+ 4(-3-3) + 6(3-k)] = 02k + 6 - 24 + 18 - 6k = 02k + 24 - 24 - 6k = 0-4k = 0k = 0

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