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four years ago the age of a father was exceeding by 2 years then 4 times the age of his son after 3 years the father will be less by 4 years than thrice the age of the son |
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Answer» LET the present ages of the father be x years and the son b y years therefore according to the question case 1: x-4=4(y-4)+2 x-4= 4Y- 16 +2 = 4y-14 x-4y = -10......eq 1 case 2:X + 3 =3( Y + 3) - 4= 3Y + 9 - 4 X + 3 =3y + 5 X - 3Y =2.......eq2 subtracting equation 1 and equation 2 we get Y = 12 substituting this value of Y in equation 2 we get X - 36 = 2 x = 36 + 2 x = 38 Thus, the AGE of father is 38 years and the age of his son is 12 years |
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