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Four resistances of `3Omega, 3Omega, 3Omega and 4Omega` respectively are used to form a Wheatstone bridge. The `4Omega` resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will beA. `10Omega`B. `11Omega`C. `12Omega`D. `13Omega` |
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Answer» Correct Answer - C The bridge will be balanced when the shunted resistance is of the value of `3Omega` `therefore 3=(4xxR)/(4+R) ,12+3=4R, therefore R=12Omega` |
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