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Four point charges q_(A) =2 muC, q_(B) = -5 muC, q_(C) =2 muC, and q_(D) = -5 muCare located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 muCplaced at the centre of the square ? |
Answer» Solution :Situation GIVEN in the statement is depicted ii the FOLLOWING figure.  Magnitude of Coulombian force exerted of `q_(0)` by `q_(A)` is, `F_(OA) = K(q_(0)q_(A))/R^(2)` (From A to O) …………..(1) Magnitude of Coulombian force exerted on `q_(0)` by `q_(C)`, is `F_(OC) =k(q_(0)q_(C))/r^(2) = k(q_(0)q_(A))/r^(2) (THEREFORE q_(C) = q_(A))` From C to O ..........(2) From eqn (1) and (2) `vecF_(OA) = -vecF_(OC)`...........(3) Magnitude of Coulombian force exerted on `q_(0)` by `q_(B)` is `F_(OB) = k(q_(0)q_(B))/r^(2)` (From O to B)...........(4) `F_(OB) = -F_(OB)`..........(6) Now, resultant Coulombian force exerted on `q_0` by remaining charges is, `vecF_(O) = vecF_(OA) + vecF_(OB) + vecF_(OC) + vecF_(OD) = vecO` `therefore F_(O) =0` |
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