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Four moles of carbon monoxide anre mixed with four moles of carbon dioxide. Asuming the gases to be ideal, the ratio of specific heats is : |
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Answer» `15//11` `gamma =(n_(1)C_(p1)+n_(2)C_(P2))/(n_(1)C_(v1)+n_(2)C_(v2))` As `C_(p) and C_(v)` of DIATOMIC gas have values `(7R)/(2) and (5R)/(2)` whereas their values for polyatomic gas are 4R and 3R. So on substituting these values we get `gamma =(15)/(11)`. Correct choice is (a). |
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