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Four diatomic species are listed in different sequence .Which of these represent the correct order of their increasing bond order?A. `NO lt C_(2)^(2-) lt O_(2)^(-) lt He_(2)^(+)`B. ` C_(2)^(2-) lt He_(2)^(+) lt O_(2)^(-)`C. ` HE_(2)^(+) lt O_(2)^(-) lt NO lt C_(2)^(2-)`D. `O_(2)^(-) lt NO lt C_(2)^(2-) lt He_(2)^(+)` |
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Answer» Correct Answer - c B.O. of `NO = (1)/(2) (8 - 3) = (5)/(2) = 2.5` B.O. of `C_(2)^(-) = (1)/(2) (8 - 2) = (6)/(2) = 3` B.O. of `O_(2)^(-) = (1)/(2) (8 - 5) = (3)/(2) = 1.5` B O of `He_(2)^(+) = (1)/(2) (2 - 1) = (1)/(2) = 0.5` `rArr "B.O. is" C_(2)^(-) gt NO gt O_(2)^(-) gt He_(2)^(+)` |
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