Four concentric circles share the same centre. The smallest circle has a radius of 1 inch. For n ≥ 1, the area of the nth smallest circle in square inches, An, is given by An+1=An+(2n+1)π. What is the ratio of the sum of the areas of the four circles to the sum of their circumferences?

Four concentric circles share the same centre. The smallest circle has

1.	Four concentric circles share the same centre. The smallest circle has a radius of 1 inch. For n ≥ 1, the area of the nth smallest circle in square inches, An, is given by An+1=An+(2n+1)π. What is the ratio of the sum of the areas of the four circles to the sum of their circumferences?
Answer» Four concentric circles share the same centre. The smallest circle has a radius of 1 inch. For n ≥ 1, the area of the nth smallest circle in square inches, A_n, is given by $A_{n + 1} = A_{n} + (2 n + 1) π$ . What is the ratio of the sum of the areas of the four circles to the sum of their circumferences?

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Four concentric circles share the same centre. The smallest circle has a radius of 1 inch. For n ≥ 1, the area of the nth smallest circle in square inches, An, is given by An+1=An+(2n+1)π. What is the ratio of the sum of the areas of the four circles to the sum of their circumferences?

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