Four charges are placed at thecorners of a square of side a. ABD are +

1.	Four charges are placed at thecorners of a square of side a. ABD are +q and C is -q. find net force on the charge at corner C
Answer» Answer: F = KQq/r² hence , magnitude of force depends UPON products of magnitude of charges and distance between them . but here distance between charge particle is fixed so, only depends upon product of magnitude of charge . we KNOW smallest charge = 1.6 × 10-19C of electrons exist in NATURE . so, if we CHOOSE both charge particle " electrons " then force will be minimum. now, F = Ke²/r² = 9× 10^9 × (1.6 × 10^-19)²/(1/100)² = 9 × 2.56 × 10^-29+4 N = 23.04 × 10^-25 N = 2.304 × 10^-24 N 4.6

Four charges are placed at thecorners of a square of side a. ABD are +q and C is -q. find net force on the charge at corner C

Answer»

Answer:

F = KQq/r²

hence , magnitude of force depends UPON products of magnitude of charges

and distance between them .

but here distance between charge particle is fixed so,

only depends upon product of magnitude of charge .

we KNOW smallest charge = 1.6 × 10-19C

of electrons exist in NATURE .

so, if we CHOOSE both charge particle " electrons " then force will be minimum.

now,

F = Ke²/r²

= 9× 10^9 × (1.6 × 10^-19)²/(1/100)²

= 9 × 2.56 × 10^-29+4 N

= 23.04 × 10^-25 N

= 2.304 × 10^-24 N

4.6

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Four charges are placed at thecorners of a square of side a. ABD are +q and C is -q. find net force on the charge at corner C​

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Four charges are placed at thecorners of a square of side a. ABD are +q and C is -q. find net force on the charge at corner C