Form the pair of linear equations in the following problems, and find

1.	Form the pair of linear equations in the following problems, and find their solutions(i) Ifwe add i to the numerator and subtract l from the denominator, afraction reducesto 1. It becomes if we only add 1 to the denominator. What is the fraction?(if they exist) by the elimination method:
Answer» Let numerator be x and denominator be y For first condition(x + 1) / (y - 1) = 1x + 1 = y - 1x - y = - 2......(1) For second conditionx/(y + 1) = 1/22x = y + 12x - y = 1.....(2) Subtract eq(1) from eq(2), we get 2x - x = 1 - (-2)x = 3 Put value of x = 3 in eq(1)3 - y = - 2y = 3+2 = 5 Therefore fraction = x/y = 3/5

Form the pair of linear equations in the following problems, and find their solutions(i) Ifwe add i to the numerator and subtract l from the denominator, afraction reducesto 1. It becomes if we only add 1 to the denominator. What is the fraction?(if they exist) by the elimination method:

Answer»

Let numerator be x and denominator be y

For first condition(x + 1) / (y - 1) = 1x + 1 = y - 1x - y = - 2......(1)

For second conditionx/(y + 1) = 1/22x = y + 12x - y = 1.....(2)

Subtract eq(1) from eq(2), we get 2x - x = 1 - (-2)x = 3

Put value of x = 3 in eq(1)3 - y = - 2y = 3+2 = 5

Therefore fraction = x/y = 3/5