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Form the differential equation of family of lines concurrent at theorigin.A. `x(dy)/(dx)-y=0`B. `x+(dy)/(dx)=0`C. `(dy)/(dx)=0`D. `(dy)/(dx)=x` |
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Answer» Correct Answer - A The equation of the family of lines passing through the origin is `y=mx" …(i)"` `rArr" "(dy)/(dx)=m" …(ii)"` From (i) and (ii), we get `y=x(dy)/(dx)`, which is the required differential equation. |
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