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Form the differential equation of family of lines concurrent at theorigin.A. `x(dy)/(dx)-y=0`B. `x+(dy)/(dx)=0`C. `(dy)/(dx)=0`D. `(dy)/(dx)=x`

Answer» Correct Answer - A
The equation of the family of lines passing through the origin is
`y=mx" …(i)"`
`rArr" "(dy)/(dx)=m" …(ii)"`
From (i) and (ii), we get
`y=x(dy)/(dx)`, which is the required differential equation.


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