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Form a quadratic polynomial whose one zero is 3+√2 |
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Answer» Answer: Step-by-step explanation: Let α and β are the zeroes of a quadratic polynomial. Given: ONE zero(α)= 3+√2 Sum of its zeroes (α+ β)= 6 (α+ β)= 6 3+√2 + β= 6 β = 6- (3+√2)= 6 -3 -√2= 3-√2 β= 3 -√2 Product of zeroes (α. β) = (3+√2) (3-√2) [(a+b) (a-b)= a² - b²] α. β = 7 Required Polynomial= k [x²-(Sum of zeroes)X +( Product of zeroes)] = k[ x² -(α+ β)x +(α. β], where k is a non zero real number. = x² -(6)x + (7) [ here k = 1] = x² - 6x + 7 Hence, a quadratic polynomial is x² - 6x + 7. HOPE THIS WILL HELP YOU... |
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