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Force on a particle in one-dimensional motion is given by `F=Av+Bt+(Cx)/(At+D)`, where F= force, v= speed, t= time, x= position and A, B, C and D are constants. Dimension of C will be-A. `M^(2)L^(-2)T^(0)`B. `ML^(-1)T(0)`C. `M^(2)L^(0)T^(-2)`D. None of these |
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Answer» `dim(A)=((F)/(V))rArrdim(C)=dim[(F(At+D))/(x)]` `=dim[(F)/(x)((Ft)/(v))]=din[(F^(2)t)/(xv)]=dim[F^(2))/(V^(2))]=[M^(2)T^(-2)]` |
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