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force `F` on a partical moving in a straight line veries with distance `d` as shown in the figure. The work done on the partical during its displacement of `12 m` is A. `21 J`B. `26 J`C. `13 J`D. `18 J` |
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Answer» Work done = Area under `(F-x)` graph `= 2 xx (7 - 3) + (1)/(2) xx 2 xx(12 - 7)` `= 8 + (1)/(2) xx 10 = 8 + 5 = 13 J` |
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