1.

Force F is given by F=at+bt^(2). Where ''t'' is time. What are the dimensions of ''a'' and ''cb''?

Answer»

`MLT^(-3)` and `MLT^(-4)`
`MLT^(-1)` and `MLT^(0)`
`MLT^(-3)` and `MLT^(4)`
`MLT^(-4)` and `MLT`

Solution :`F= at + bt^2`
According to principle of homogeneity , the FORCE becomes,
`MLT^2 = MLT^(-2) + MLT^(-2)`
Comparing (1) and (2) , we get a `= MLT^(-3) , b= MLT^(-4)`


Discussion

No Comment Found