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Force F is given by F=at+bt^(2). Where ''t'' is time. What are the dimensions of ''a'' and ''cb''? |
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Answer» `MLT^(-3)` and `MLT^(-4)` According to principle of homogeneity , the FORCE becomes, `MLT^2 = MLT^(-2) + MLT^(-2)` Comparing (1) and (2) , we get a `= MLT^(-3) , b= MLT^(-4)` |
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