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Force F and density D are related as `F=(alpha)/(beta+sqrtd)`, Then find the dimensions of `alpha` and `beta`A. `[L^((1)/(2))M^((3)/(2))T^(-2)]`B. `[L^(-1)M^((1)/(2))T^(-2)]`C. `[L^(-1)M^((3)/(2))T^(-2)]`D. `[L^(-(1)/(2))M^((1)/(2))T^(-2)]` |
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Answer» Correct Answer - A The dimessions of force `[F] = [ML T^(-2)]` and density `[d] = [ML^(-3) T^(0)]` From the given relation, `F =(y)/(sqrt(d))` `rArr " " y = F sqrt(d)` Substituting the above dimesions, we get ` [y] = [F] [d]^(1//2) = [ML T^(-2)] [ML^(-3) T^(0)]^(1//2)` ` = [M^(3//2) L^(-1//2)T^(-2)]` |
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