Saved Bookmarks
| 1. |
Force between two identical charges placed at a distance r in vacuum is F. Now dielectic constant K=4 is inserted between these two charges . The thickness of the slab is r/2. the force between the charges will now become? |
| Answer» Force between two identical charges placed at a distance r in vacuum is F. Now dielectic constant K=4 is inserted between these two charges . The thickness of the slab is r/2. the force between the charges will now become? | |