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Force between two identical charge placed at a distance of r in vaccum is F now a slab of dielectric of dielectric constant K=4 is inserted between the two charge the thickness of slab is r/2 then find new force between two charge |
| Answer» Force between two identical charge placed at a distance of r in vaccum is F now a slab of dielectric of dielectric constant K=4 is inserted between the two charge the thickness of slab is r/2 then find new force between two charge | |