1.

Force acts on 50 kg mass changes it’s velocity from 10 m/s to 20 m/s calculate the work done

Answer»

the particle = 50 kg Initial VELOCITY = 10 m/s Final velocity = 20 m/sAccording to the WORK - energy theorem, W = ∆KE = ½ m(v + U)(v - u) ⇒ W = ½ 50(20 + 10)(20 - 10) J ⇒ W = 25(30)(10) J ⇒ W = 7500 J or 7.5 kJ. ∴ Work done on the particle was of 7.5 kJ.



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