1.

Force (5, 6, 7) N acts on a particle with position vector (2, 2, 1) m. The magnitude of phi torque on the particle will be ………. Nm.

Answer»

`sqrt(13)`
`sqrt(149)`
`sqrt(61)`
`sqrt(23)`

Solution :`|vectau|=|vecrxxvecF|`
`=|(2,2,1)xx(5,6,7)|`
`=|(2,2,1)xx(5,6,7)|`
`=|hati(14-6)-HATJ(14-5)+hatk(12-10)|`
`=|8hati-9hatj+2hatk|`
`=sqrt((8)^(2)+(-9)^(2)+(2)^(2))`
`=sqrt(64+81+4)`
`=sqrt(149)`


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